Question

Select the equation of the line graphed below:



y + 7 = 1(x + 6)


y – 7 = 1(x – 6)


y + 6 = 1(x + 7)


y – 6 = 1(x – 7)

https://static.k12.com/eli/bb/1211/4_68960/2_33580_12_68972/e1120da006e352e437dc8fe29146b21aef604445/media/79f8ace6ffc61f82a31f6c5ce5ecbce34a8a0321/mediaasset_958465_1.jpg

Answer 1

select any 2 points that lie on the line
for example - http://prntscr.com/8bp02w

and then apply 2 point form which is -

\[\frac{ y-y _{1} }{ y_{2}-y_{1} }=\frac{ x-x_{1} }{ x_{2}-x_{1} }\]

where (x1,y2) and (x2,y2) are the cordinates of the 2 points :)

Answer 2

your line passes at point (7,6). For example if I substitute x=7 and y=6, into the secondequation, I get:
\[\Large \begin{gathered}
6 - 7 = 1 \cdot \left( {7 - 6} \right) \hfill \\
\hfill \\
- 1 = 1 \hfill \\
\end{gathered} \]
which is a false statement, so the second option can not be the right option.
Please do the same with the other options

Answer 3

or u can do as @Michele_Laino said :)

select any point the lies on the line an put its x and y cordinates in the options nd the one which satisfies is the answer :)

Answer 4

but sometimes it may happen that more than 1 equation satisfy the reason is that, that point may be the solution to those lines :)

Answer 5

would it be c?

Answer 6

I think no, since if I substitute x=7 and y=6 into the third equation, I get:
\[\Large \begin{gathered}
6 + 6 = 1 \cdot \left( {7 + 7} \right) \hfill \\
\hfill \\
12 = 14 \hfill \\
\end{gathered} \]
which, again, is a flase statement

Answer 7

false*

Answer 8

so a

Answer 9

that's right!

Answer 10

thnx

Answer 11

:)