Question

In which expression should the exponents be multiplied?
one fifth to the 2nd times one fifth to the 6th
9 to the 3rd over 9 to the 4th
73 ⋅ 78
(26)−5

Answer 1

@phi

Answer 2

after this there is 2 more

Answer 3

you shout use ^ or the equation editor. I can't tell which numbers are exponents.

Answer 4

oh let me fix it

Answer 5

but we did this in your first question
\[ \left(7^3\right)^2 = 7^6\]
notice that 2*3= 6 (that is the short cut)

Answer 6

1/5^2 x 1/5^6

9^3/9^4

7^3 x 7^8

(2^6)^-5

Answer 7

do u want a screenshot ?

Answer 8

no. it's clear. can you pick out the answer?

Answer 9

ok

Answer 10

let me see

Answer 11

(2^6)^-5??

Answer 12

yes. the answer is 2^(-30)
the way to get that the long way is "flip" and make -5 +5
\[ \left(2^6\right)^{-5}= \frac{1}{\left(2^6\right)^{5}}= \frac{1}{2^6\cdot 2^6 \cdot 2^6\cdot 2^6\cdot 2^6}\]

Answer 13

ok

Answer 14

2^6 is 2*2*2*2*2*2
and there are 5 of those, which adds up to 2 times itself 30 times.

Answer 15

so when its multiplied up its 2^-(30) because 6x5 is 30

Answer 16

oh

Answer 17

ok ya

Answer 18

if you learn to do it the "hard way" it should make sense.
and the short cuts will be easier to understand.

Answer 19

lol ok

Answer 20

alrighty thanks for the awesome help again i got 2 left