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Algebra 15 Online
OpenStudy (anonymous):

formula to find the vertex of y=2(x+1)square-1

OpenStudy (anonymous):

Vertex for being y=a(x-h)^2 +k, you just need to plug in the numbers and do the math

OpenStudy (anonymous):

I don't really get you question, are you trying to find the vertex?

OpenStudy (anonymous):

normaly i m using -b over 2a to find the vertex, where should i use at here?

OpenStudy (anonymous):

it depends on what you are trying to find.

OpenStudy (anonymous):

the vertex. I know y=(a)square+bx+c using -b over 2a to find the vertex, but how could i find the vertex at here?

OpenStudy (anonymous):

well, the equation is already in vertex form, so just solve.

OpenStudy (anonymous):

i don't get. I know the vertex is (-1,-1). But I need to show how i find the vertex

OpenStudy (anonymous):

hang on, lemme put it in geo gebra

OpenStudy (anonymous):

kk

OpenStudy (anonymous):

that's it, the vertex is at( -1 -1) you had it. You just need to show how you get it?

OpenStudy (anonymous):

yes, that is what i m asking

OpenStudy (anonymous):

Well, how i did it is i put the equation into my graphing software and the lowest point of the graph is the vertex|dw:1441240202409:dw|

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