You order 1.5 pounds of turkey at a deli. You will accept the turkey if its weight is between 1.54 lb and 1.46 lb. What absolute value inequality describes the tolerance of the weight of the turkey?
Please help I am a bit confused, thank you
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jimthompson5910 (jim_thompson5910):
draw a number line and plot 1.5 on it
|dw:1441251633221:dw|
preferably in the center
jimthompson5910 (jim_thompson5910):
then add on 1.54 and 1.46
|dw:1441251655628:dw|
jimthompson5910 (jim_thompson5910):
how far is 1.54 from 1.5 ?
OpenStudy (anonymous):
.04
jimthompson5910 (jim_thompson5910):
|dw:1441251739315:dw|
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jimthompson5910 (jim_thompson5910):
how about from 1.46 to 1.5 ?
OpenStudy (anonymous):
Would it be |x-1.5|>=0.04
jimthompson5910 (jim_thompson5910):
very close
OpenStudy (anonymous):
Wait |x-1.5|=<0.04???
jimthompson5910 (jim_thompson5910):
the general form is
|x - T| <= E
T = target value
E = error
you want the absolute value of the difference, |x-T|, to be as small as possible. Ideally 0
The worst you're able to live with is E = 0.04
so yeah it should be |x-1.5| <= 0.04
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