The point-slope form of the equation of the line that passes through (–4, –3) and (12, 1) is y – 1 = (x – 12). What is the standard form of the equation for this line?
(A) x – 4y = 8
(B) x – 4y = 2
(C) 4x – y = 8
(D) 4x – y = 2

Question

The point-slope form of the equation of the line that passes through (–4, –3) and (12, 1) is y – 1 = (x – 12). What is the standard form of the equation for this line?
(A) x – 4y = 8
(B) x – 4y = 2
(C) 4x – y = 8
(D) 4x – y = 2

anonymous · Answer

?

welshfella · Answer

slope of the line = ( 1 - (-3) /  12 - (-4) = 4/16 = 1/4

plugging in y = -3 , x = -4 and m = 1/4 into the point-slope form:-

y - (-3) = (1/4)(x - (-4)
y + 3 = (1/4) x + 1
multiply through by 4
4y + 12 = x + 4

can you continue/

anonymous · Answer

ima try to

welshfella · Answer

subtract 4 from both sides
4y + 8 = x
subtract 4y from both sides
8 = x - 4y
which is the same as
x - 4y = 8   Standard form

welshfella · Answer

the last step was just swapping sides

anonymous · Answer

okay i got it thank you?