Question

(6^?)^-4 = 6^20

Answer 1

@Lady.Liv1776 @Nnesha @pooja195 Pls help

Answer 2

\[\huge\rm (6^?)^{-4} = 6^{20}\] am ir right ?

Answer 3

Yes

Answer 4

exponent rule \[\huge\rm (x^m)^n=x^{m \times n}\]

Answer 5

m=20*(-4) ?

Answer 6

well m is missing exponent
n =-4
so basically thats mean
m times n = -20

Answer 7

okay i kinda get it

Answer 8

\[\huge\rm (6^\color{ReD}{?})^{\color{blue}{-4}} = 6^{\color{purple}{20}}\] \[\huge\rm (x^\color{Red}{m})^\color{blue}{n}=x^{\color{red}{m} \times\color{blue}{ n}} =x^{\color{purple}{mn}}\]

Answer 9

\(\color{blue}{\text{Originally Posted by}}\) @pielover123
m=20*(-4) ?
\(\color{blue}{\text{End of Quote}}\)
this should be -4 * m = 20

Answer 10

Okay so -4*m which is -4m then times it by 20? which would be -80m?

Answer 11

why did you mutliply -4m by 20 ?

Answer 12

-4m =20 how would you solve for m ?

Answer 13

in other words m times n = 20
-4 times what = 20 ?

Answer 14

-4*5 right?

Answer 15

-4 times 5 = ??

Answer 16

is -20

Answer 17

now look at the original question is it 6^{-20} ?

Answer 18

Im confused now sorry

Answer 19

let samy missing exponent is m \[\huge\rm (6^m)^{-4}=6^{m \times -4}=6^{20}\]
m would be what ?

Answer 20

-4 times 5 = -20 but there is positive 20

Answer 21

so make them all a negative?

Answer 22

what do you mean by `all` 20 as well ?

Answer 23

yes

Answer 24

or you can set it like this -4m =20 solve for m

Answer 25

we have to prove it that left side is equal to right side
we can't change the right hand side

Answer 26

\[\rm -4m=20\] solve for m plz

Answer 27

5 right?

Answer 28

20/-4= ?

Answer 29

remember `negative ` times ` negative` = positive
`negative ` divide by `negative` = positive

Answer 30

negative times positive = negative
negative divide by positive number = negative

Answer 31

so it s -5 then

Answer 32

yes right!

Answer 33

-4 times -5 = 20

Answer 34

6^-5 is right then

Answer 35

yep right

Answer 36

thanks :D

Answer 37

np D: