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Solve the equation.
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\[3^{1/2} + 5^{1/4} -2 =0\]
where is the variable?
Oops, sorrry. It's \[3x^{1/2} + 5x^{1/4} - 2=0\]
if we let y = x^(1/4) then x^(1/2) = y^2 so we need to solve 3y^2 + 5y - 2 = 0
can you solve that / It will factor
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Okay. I understand. Doesn't that get you 1/3 and -2, but the -2 goes away?
solution is 1/3 and - 2 yes
And then what?
so we have x^(1/4) = 1/3 which is easy to solve x^(1/4) = -2 has no real solutions
Can you tell me how to solve it?
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x^(1/4) = 1/3 take 4th power of each side x = (1/3)^4 = ?
= 1 / 3^4 = 1/81
ok?
Makes sense. Thanks so much!
yw
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