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Mathematics 24 Online
OpenStudy (mathmath333):

There are 7 different books in a library. A girl can borrow book B if only book A is borrowed. In how many ways can she borrow 3 books ?

OpenStudy (mathmath333):

\(\large \color{black}{\begin{align} & \normalsize \text{There are 7 different books in a library. }\hspace{.33em}\\~\\ & \normalsize \text{A girl can borrow book B if only book A is borrowed.} \hspace{.33em}\\~\\ & \normalsize \text{In how many ways can she borrow 3 books ?} \hspace{.33em}\\~\\ & a.)\ 15 \hspace{.33em}\\~\\ & b.)\ 20 \hspace{.33em}\\~\\ & c.)\ 25 \hspace{.33em}\\~\\ & d.)\ 30 \hspace{.33em}\\~\\ \end{align}}\)

OpenStudy (anonymous):

is there any specific arrange for A and B ?

OpenStudy (mathmate):

``` A girl can borrow book B if only book A is borrowed ``` Must book A be borrowed by the girl or by someone else?

OpenStudy (phi):

25

OpenStudy (mathmath333):

book B can be borrowed only if book A is borrowed

OpenStudy (mathmath333):

yes 25 is answer given , how u got it

OpenStudy (zzr0ck3r):

I am confused by the question. But phi is not :)

OpenStudy (mathmath333):

"A girl can borrow book B if only book A is borrowed" i think "Must book A be borrowed by the girl "

OpenStudy (mathmath333):

lol m also confused by thhe question

OpenStudy (mathmate):

"A girl can borrow book B if only she also borrows book A" is the intended wording if 25 is the final answer.

OpenStudy (phi):

First, order does not matter. I broke the problem into two parts. say one of the 3 books we choose is A. then we have a choice of 6C2 for the other two. that is 15 combinations say we did not choose A. then that means we can not choose B either. that leaves 5 books from which to choose 3 5C3= 10 more combinations 15+10= 25

OpenStudy (mathmath333):

"A girl can borrow book B if only she also borrows book A" is the intended wording if 25 is the final answer. yea i think so ,

OpenStudy (mathmath333):

thnx

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