Question

What are the solutions to the quadratic equation 4x^2 + 28x = 0?

Answer 1

@Nnesha

Answer 2

the options

x = 4 and x = −7
x = 4 and x = 7
x = 0 and x = −7
x = 0 and x = 7

Answer 3

would you like to factor it
or do you want to use quadratic formula ?

Answer 4

quadratic formula

Answer 5

alright then \[\huge\rm x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a}\]
where a b c are \[\huge\rm Ax^2+Bx+C=0\]
a= leading coefficient
b=middle term
c=constant term
substitute

Answer 6

so its, 4x^2 + 28x = 0? but theres no c

Answer 7

yes right so substitute c for 0

Answer 8

Oh, okay

Answer 9

ye :D

Answer 10

Would I plug in those numbers?

Answer 11

yes a= ??
b= ?

Answer 12

a=4 and b=28, right

Answer 13

yes right

Answer 14

so then the whole equation is 4x^2 +28x +0=0

Answer 15

yes right
so substitute
a for 4
b for 28 and c for 0

Answer 16

ye