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AP Physics 23 Online
OpenStudy (bloomlocke367):

more homework check xp

OpenStudy (bloomlocke367):

OpenStudy (bloomlocke367):

@Shalante

OpenStudy (anonymous):

Hard to see. >.<

OpenStudy (bloomlocke367):

sorryyyyyy

OpenStudy (anonymous):

It requires real effort to look at one line.

OpenStudy (bloomlocke367):

I can see it clearly o.o I'm sorryyyyy

OpenStudy (anonymous):

I do not want to check your work, but just do the problem. (Hard to see your work as well)

OpenStudy (bloomlocke367):

wait... my work is hard to see.. but I can see the problems XD If you get something different I'll just ask about it lol

OpenStudy (anonymous):

Only checked the first 2. Lemme see the rest? And do you want me check all the problems?

OpenStudy (bloomlocke367):

I would like it.. but you don't have to lol... I think I'm doing a better job than last time with this stuff

OpenStudy (anonymous):

Glad to hear that.

OpenStudy (anonymous):

Holy sheet. Another worksheet.

OpenStudy (bloomlocke367):

yea.. 19 problems for one night... plus a worksheet from last week that I haven't continued on yet lol (that's the one you helped with last time lol)

OpenStudy (anonymous):

1. is correct.

OpenStudy (bloomlocke367):

yayyy

OpenStudy (anonymous):

2 and 3 is correct

OpenStudy (bloomlocke367):

woooo I am getting better XD

OpenStudy (bloomlocke367):

you deserve like 50 gazillion medals btw XD

OpenStudy (anonymous):

Lol, no need.

OpenStudy (bloomlocke367):

you're awesome omg

OpenStudy (anonymous):

4 and 5 are correct.

OpenStudy (bloomlocke367):

woooo

OpenStudy (anonymous):

Only to you. :p

OpenStudy (bloomlocke367):

hehe thanks xp I don't see why tho

OpenStudy (anonymous):

6 is correct. 100% on first worksheet. Nice!!!

OpenStudy (anonymous):

Hey, I forgot to check sf. 1 and 2 are correct but not the right # of sf.

OpenStudy (bloomlocke367):

wooooooo

OpenStudy (bloomlocke367):

and he doesn't really care about sig figs right now but thanks c: I try getting them anyways for practice. I'll look and fix it

OpenStudy (bloomlocke367):

1... 50m/s? that drops it to 1 sig fig.. 2...4.0m/s^2?

OpenStudy (anonymous):

I'll check the sf at the end. For 3. You can use only one formula to find the answer. \[x _{f}=x _{i}+v _{_{i}}t+\frac{ 1 }{ 2 }at^2\]

OpenStudy (bloomlocke367):

I haven't seen that formula before O.O

OpenStudy (bloomlocke367):

We only have 4

OpenStudy (bloomlocke367):

nevermind.. yes I have XD

OpenStudy (bloomlocke367):

lol

OpenStudy (bloomlocke367):

but I still got the right answer, right?

OpenStudy (anonymous):

Same goes for 5. 4 is correct.

OpenStudy (anonymous):

Wait nvm you would still need 2. Your way is faster for 5.

OpenStudy (bloomlocke367):

haha thanks xp

OpenStudy (bloomlocke367):

did I get 3 right?

OpenStudy (anonymous):

You're not stuck on 6 right? You are just taking a break?

OpenStudy (anonymous):

Yes.

OpenStudy (anonymous):

Plug in the values to the equation I gave you and it would still be the same with by just using 1 formula.

OpenStudy (bloomlocke367):

I'm on 8 right now lol

OpenStudy (anonymous):

Nice!

OpenStudy (bloomlocke367):

I got 1.5m for 6 and -0.13m/s^2

OpenStudy (bloomlocke367):

for 7

OpenStudy (bloomlocke367):

well I got the final velocity to be 9.6m/s then I used the formula \(v^2=v_0^2+2a(x-x_0)\)

OpenStudy (anonymous):

9.6^2=92.16m 92.16m=0+2(3.2m/s^2)(d) 92.16m/6.4m/s^2=14.4m or 14m when rounded to sf.

OpenStudy (anonymous):

You can tell your answer is wrong by reading the problem and thinking like this :

OpenStudy (anonymous):

Hmm, if a car accelerate for 3.2m/s^2 for 3 sec straight, wouldn't the distance be more than like around 5m?

OpenStudy (anonymous):

It speeds up by 3.2m/s^2 every second

OpenStudy (bloomlocke367):

OMG I SEE MY MISTAKE

OpenStudy (bloomlocke367):

I didn't square 9.6 lol

OpenStudy (bloomlocke367):

I dunno if I got 8 correct... i got 25m/s after I rounded

OpenStudy (anonymous):

lol

OpenStudy (anonymous):

7 is correct.

OpenStudy (anonymous):

Foe 8, I got the same results.

OpenStudy (bloomlocke367):

oki yay

OpenStudy (bloomlocke367):

I'm starting on 9 now

OpenStudy (bloomlocke367):

I got no for 9.. because the final velocity is 5m/s

OpenStudy (bloomlocke367):

is that right?

OpenStudy (bloomlocke367):

OMG http://prntscr.com/8e69uy

OpenStudy (anonymous):

LMAO

OpenStudy (anonymous):

For 9, I got no because it would be at 25m/s 0.0

OpenStudy (bloomlocke367):

that's what I meant lol

OpenStudy (bloomlocke367):

sorry XD I have issues typing the right numbers for some reason XD

OpenStudy (anonymous):

Lol, no wonder.

OpenStudy (bloomlocke367):

what would I do for 10?

OpenStudy (anonymous):

Hint: one formula.

OpenStudy (bloomlocke367):

hang on.. I may be able to figure it out

OpenStudy (bloomlocke367):

the formula you showed me right..

OpenStudy (bloomlocke367):

?

OpenStudy (anonymous):

yes

OpenStudy (bloomlocke367):

gimme a sec.. everyone is talking

OpenStudy (bloomlocke367):

you can't add t and t^2, can you?

OpenStudy (bloomlocke367):

OMG I KNOW WHAT TO DO.. I CAN USE THE QUADRATIC FORMULA

OpenStudy (bloomlocke367):

wait.. I got both negative answers..but it's time.. @Shalante can you walk me through this?

OpenStudy (bloomlocke367):

wait... nevermind xp I graphed it and got 4.. is it 4 seconds?

OpenStudy (anonymous):

You would need quadratic, which is a pain. So the one formula I told you to use was bad. vf^2=v^i+2ax then vf=vi+at is better.

OpenStudy (anonymous):

If you are given everything except time in the formula, then it would be a good idea to use that 1 formula.

OpenStudy (bloomlocke367):

ok.. sorry I'm getting stressed

OpenStudy (bloomlocke367):

so which one?

OpenStudy (bloomlocke367):

ohhh do the two separate ones like I have been?

OpenStudy (anonymous):

You got 4 right. Did you do it using 1 formula or 2?

OpenStudy (bloomlocke367):

I graphed the quadratic from the first equation you had me use xp

OpenStudy (anonymous):

Either way works but the one formula is annoying since it has a quadratic.

OpenStudy (anonymous):

Dont do that next time. I messed up also because I hinted you to do it in 1 formula instead of 2.

OpenStudy (anonymous):

vf^2=v^i+2ax then vf=vi+at

OpenStudy (bloomlocke367):

bc I tried the quadratic formula but messed up then I just graphed it XD

OpenStudy (bloomlocke367):

OMG I FOUND MY MISTAKE AND GOT IT WITH THE QUADRATIC FORMULA :D

OpenStudy (anonymous):

Ok next question.

OpenStudy (bloomlocke367):

ok.. idk what to do here

OpenStudy (anonymous):

Are you focusing better right now? Because this question is similar to the ones you done.

OpenStudy (bloomlocke367):

no I'm not tbh

OpenStudy (bloomlocke367):

I GOT IT

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