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\[\frac{ 4 }{ t-2 } - \frac{ 8 }{ t ^{2} -2t} = -2\]
help pls
i beg
ok
first step take lcm of the denominators
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what do you get
is the lcm t-2(t^2-2t)
yes
and then i multiple that to the numerators
good
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thankss i think im good from there on :)
then what do you get
oh im still up to that step lol, i had trouble finding lcd
you need help
it will come to 4t^2-16t+16/(t-2)(t^2-2t)=-2
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hey how far did you go
my answer came out weird
why?
I multiplied the LCD by the numerators but instead of 4t^2-16t+16 i got 4t^2-16t+8
|dw:1441777449360:dw|
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