Question

Help! Will medal/fan!

Answer 1

Given that f(x) = 3x + 1 and g(x) = the quantity of 4x plus 2 divided by 3, solve for g(f(0)).

2
6
8
9

Answer 2

The best way to think about this problem is what are you plugging int to what?

g(f(0)) means, you plug 0 into f(x).

Whatever number you get from that, you plug into g(x)!

Answer 3

I'm really confused, Please walk me through it...

Answer 4

If I plug in 0 for f(x)...

Answer 5

4(3x+1)+234(3x+1)+23
First let's find F(0).

Plug in 0 for x in F(x)

F(x) = 3x +1
F(0) = 3(0) + 1
F(0) = 0 +1
F(0) = 1

Answer 6

Okay I wasn't sure what you meant by the plugging 0 into f(x) But I get it now,

Answer 7

So now, you plug in 1 into g(x)

G(1) = ?????

G(x)=
4x+23

G(1)=
4(1)+23

G(1)=
63

G(1)=
21
= 2
G(1)=2

Answer 8

Okay thanks! Now I will know how to do the rest!

Answer 9

cx awesome