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Algebra 14 Online
OpenStudy (anonymous):

3(p + q) = p

OpenStudy (rushwr):

What do we have to find here ?

OpenStudy (anonymous):

3p + q = p q = -2p

OpenStudy (rushwr):

actually that should be 3p +3q = p

OpenStudy (♪chibiterasu):

You have to distribute the 3 so it's 3q not just q.

OpenStudy (anonymous):

A.Q= -2/3p B.Q= -3/2p C.P= -2/3q D.P = -3/2q

OpenStudy (rushwr):

\[3(p+q) = p\]

OpenStudy (rushwr):

\[3p + 3q = p \]

OpenStudy (rushwr):

\[3p-p = -3q\]

OpenStudy (rushwr):

\[2p = -3q \]

OpenStudy (rushwr):

\[p = \frac{ -3q }{ 2 }\]

OpenStudy (rushwr):

Since we don't have a correct answer for p we will find a value for Q 3p+3q = p 3q = p - 3p = -2p 3q= -2p q= -2p divided by 3

OpenStudy (anonymous):

p = -3/2q is correct

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