given f(x)=-x^2+2x, find f(-3) will medal and fan :3
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Nnesha (nnesha):
f(-3)
that means x =-3
so substitute x for -3 into f(x)=-x^2+2x
OpenStudy (anonymous):
f(-3)=-3x^2+2(3)
OpenStudy (anonymous):
i didn't mean that x after 3...
Nnesha (nnesha):
alright it should be -(-3)^2+2(-3) now solve this
OpenStudy (anonymous):
-(-9)+-6
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Nnesha (nnesha):
when you take even power of negative number you will always get positive answer
OpenStudy (anonymous):
so 9+6?
Nnesha (nnesha):
\[\huge\rm -\color{ReD}{x}^2+2\color{ReD}{x}\]this is the function
replace x with -3 \[\huge\rm -(\color{ReD}{-3})^2+2(\color{ReD}{-3})\]
2 times -3 = ?
OpenStudy (anonymous):
-6
Nnesha (nnesha):
yes right \[-(-3)^2-6\] solve
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OpenStudy (anonymous):
9-6=3
Nnesha (nnesha):
(-3)^2 = 9
there is a negative sign front of the parentheses
OpenStudy (anonymous):
but you said two negatives make a positive????
Nnesha (nnesha):
yes right so (-3)^2 = -3 times -3= 9
OpenStudy (anonymous):
i got 9 and i plugged it into the equation and that's how i got 3
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Nnesha (nnesha):
\[\huge\rm\color{blue}{ -}\color{ReD}{x}^2+2\color{ReD}{x}\]this is the function
replace x with -3 \[\huge\rm \color{blue}{-}(\color{ReD}{-3})^2+2(\color{ReD}{-3})\]
\[\huge\rm \color{blue}{-}(\color{ReD}{9})-6\]
(-3)^2 =9
but i'm saying blue sign would stay there