given f(x)=-x^2+2x, find f(-3) will medal and fan :3
f(-3) that means x =-3 so substitute x for -3 into f(x)=-x^2+2x
f(-3)=-3x^2+2(3)
i didn't mean that x after 3...
alright it should be -(-3)^2+2(-3) now solve this
-(-9)+-6
when you take even power of negative number you will always get positive answer
so 9+6?
\[\huge\rm -\color{ReD}{x}^2+2\color{ReD}{x}\]this is the function replace x with -3 \[\huge\rm -(\color{ReD}{-3})^2+2(\color{ReD}{-3})\] 2 times -3 = ?
-6
yes right \[-(-3)^2-6\] solve
9-6=3
(-3)^2 = 9 there is a negative sign front of the parentheses
but you said two negatives make a positive????
yes right so (-3)^2 = -3 times -3= 9
i got 9 and i plugged it into the equation and that's how i got 3
\[\huge\rm\color{blue}{ -}\color{ReD}{x}^2+2\color{ReD}{x}\]this is the function replace x with -3 \[\huge\rm \color{blue}{-}(\color{ReD}{-3})^2+2(\color{ReD}{-3})\] \[\huge\rm \color{blue}{-}(\color{ReD}{9})-6\] (-3)^2 =9 but i'm saying blue sign would stay there
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