Question

Rewrite the equation y = 3x^2 + 6x + 2 in the alternate form and state the vertex point.

Answer 1

do you see how y = 3x^2 + 6x + 2 is in the form y = ax^2 + bx + c ?

Answer 2

a = 3 b = 6 c = 2?

Answer 3

yep

Answer 4

now plug the values of a,b into h = -b/(2a)
what is the value of h?

Answer 5

h = -1?

Answer 6

yes

Answer 7

now plug that value in for x to find y

y = 3x^2 + 6x + 2
y = 3(-1)^2 + 6(-1) + 2
y = ???

Answer 8

Is it -1?

Answer 9

correct

Answer 10

so k = -1

Answer 11

we have
a = 3, h = -1 and k = -1

plug those into

y = a(x-h)^2 + k

Answer 12

Does x = 6?

Answer 13

where are you getting x = 6 ?

Answer 14

Oh thought x = 6 from the problem. Dont know what x is.

Answer 15

x is just a variable to be left alone really

Answer 16

what did you get when you plugged those values into y = a(x-h)^2 + k

Answer 17

Is it 11?

Answer 18

don't replace x though

Answer 19

Oh keep x as just x?

Answer 20

yes

Answer 21

So is this right? y - 3(x - (-1)^2 + - 1 . I think I set it up wrong.

Answer 22

I meant y =

Answer 23

if you simplified that, you'd get what?

Answer 24

Does the 3 go with the things inside the ( )

Answer 25

no