Question

if m and n are whole odd numbers, is true that m^2 + n^2 is always:
a) perfect square
b) divisible by 4
c) even
d) odd

I need to show how do it, PLZ help
b)

Answer 1

@imqwerty

Answer 2

@Mehek14

Answer 3

2n+ 1

Answer 4

i guess where n is a whole number

Answer 5

is not the same ?

Answer 6

by i need to show this by algebra not basic math

Answer 7

(2n+1) ^2 + (2m +1)^2 = 4n^2+ 4n + 1 + 4m^2 +4m +1

Answer 8

4( n^2 + m^2+ m +n) +2

Answer 9

is that enough to prove the answer ?

Answer 10

i guess 4(m^2 + n^2 +m + n) always has to be even and even +2 remains the same ..

Answer 11

right ?

Answer 12

4( n^2 + m^2+ m +n) +2, yeah this is enough to prove evenness.

Answer 13

I mean, it's a number divisible by 4 plus 2. I'm pretty convinced it's even, on a human level :)

Answer 14

thanks dude!

Answer 15

no problem