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How many 3x3 and 4x4 matrices with or without complex entries (the distinction is important) square to the negative of the identity matrix?
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how many?
Deleted previous answer which was probably incorrect :)
I'm compelled to say that only \(A=iI\) satisfies the condition \(A^2=-I\) for any matrix of size \(n\). Perhaps it's possible to prove uniqueness by contradiction, but it's not obvious to me at the moment.
Doesn't rotation by pi satisfy in n = 2? I think something similar works in any even dimension.
@nettle404
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What rotation maps itself to \(-I\)? My matrix algebra is a bit rusty, so you may have to point out an obvious mistake of mine.
|dw:1442115826437:dw| I mean like this.
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