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Functions and inverses If ƒ(x ) = 3x + 1 and ƒ ^-1 = x-1/3 then ƒ(2) = 1/3 1 7
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Any help would be great.
f(2) means you just replace the x's in the function named f above
you have f(x)=3x+1 you want to find f(2) replace the x's with 2
7 or 1/3
?
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well you are to find f(2) not f^(-1)(2)
so what do you think?
So 7
yes
3*2+1= 7
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Thanks.
np
Can I check 1 more? If ƒ(x ) = 3x + 1 and ƒ ^-1 = x-1/3 then ƒ ^-1(7) = 22 2 -2
7-1=6/3=2
is that really (x-1)/3 or is it x-1/3 judging by what f is I believe f^-1(x)=(x-1)/3 and if so f^-1(7)=(7-1)/3=6/3=2 is right
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x-1 is over 3
or divided by 3
which ever terminology you prefer
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