Question

Three consecutive odd integers have a sum of 45. Find the integers

Answer 1

@freckles

Answer 2

So you know that the integers have to be odd, right?

Answer 3

Ya ..

Answer 4

And they have to be consecutive. (1, 2, 3)

Answer 5

So just try it! Start with 13.

Answer 6

What is 13+15+17?

Answer 7

Lol 😐😐😐😑😑 I'm dumb

Answer 8

It's simple addition. Use a calculator if you absolutely have to.

Answer 9

Can you help me with some more in a bit if I message you?

Answer 10

I'll try.

Answer 11

Thanks babe!

Answer 12

consecutive odd integers: have a difference of 2 between each of the numbers, and theyre odd, aka 1,3,5... etc \[2n + (2n+1) +(2n+3)=45\]

Answer 13

I would solve the equation
n+(n+2)+(n+4)=45

but I think @Jhannybean meant to say
(2n-1)+(2n+1)+(2n+3)=45 which is also a great route to go :)

Answer 14

Oh that's right, thanks @freckles :D