Write an equation of a line that passes through (-3, 4) with slope -. @amistre64
what formula of a line equation implements a slope and a point?
y-y1= m (x-x1)
then all we need to do is plug in the values ...
what do we end up with? and you have not posted a readable m value yet
-1/2
is the slope
ok, then i can verify your results
y-4= -1/2 (x+3)
yep, looks good. that is an equation of a line.
if need be we can rewrite it as y=(stuff) distribute and add thru the 4
but the question doesnt imply what form is required for a solution.
y=
so How would I find the y intercept
the y axis, is also the x=0 axis ... so the intercept when x=0 is found when we let x=0
y-4= -1/2 (x+3) y-4= -1/2 (0+3) y-4= -3/2 what is our y value?
2.5
so y=-1/2x +2.5
the other method which i suggested works just the same ... y-4= -1/2 (x+3) y-4= -x/2 -3/2 y= -x/2 -3/2 +4 unless you require decimals, i would keep it all in ratioed numbers y int = 5/2
not that it matters, its just a visual thing that some teachers adhere to.
I got it thank you
:) youre welcome
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