Assume that you have a total of 12 people on the committee: 3 black males, 3 black females, 1 white male, and 5 white females. Party rules require that at least one black and at least one female hold one of the three offices. Note that if individuals change offices, then a different selection exists. In how many ways can the officers be chosen while still conforming to party rules?
DO you have any options ?
restriction number , at least 1 black: C(12,6) where 12 is the total of people and 6 is the same as say 3 black men or 3 black female: \[C (12,6) = \frac{ 12! }{ (12-6)! *6! }\]
@Pulsified333 are you following ?
yes thank you very much
wait that is not the whole answer
we're missing the second part
i got the answer
how did you do it ?
P(12,3)-P(6,3)-P(4,3)
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