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Mathematics 6 Online
OpenStudy (anonymous):

Yes . . im back with another question :(( http://prntscr.com/8gfbwi

OpenStudy (anonymous):

Ok so look at the question. What are the odds someone will get a shot in every free throw?

OpenStudy (anonymous):

1 shot ? or would it have to add up to 5000?

OpenStudy (anonymous):

im guessin it going to be between A or B

OpenStudy (anonymous):

ok. Good its about one shot guessing. But realize that this will be simulated 5000 times. This means \[5*5000=25000\] That means there will be 25,000 shots total.

OpenStudy (anonymous):

So in about 419 of those simulations you will have a missed free throw ?

OpenStudy (anonymous):

Wait.

OpenStudy (anonymous):

or ? .162*5000=810

OpenStudy (anonymous):

5000-810=4190

OpenStudy (anonymous):

Seeing this again. It would seem that it would probably be about 4190.

OpenStudy (anonymous):

correct it was thanks !

OpenStudy (anonymous):

Wait which one?

OpenStudy (anonymous):

4190 was correct indeed !

OpenStudy (anonymous):

.162*5000=810 then 5000-810=4190

OpenStudy (anonymous):

ok. :P I was thinking something else when I first glanced at it so lel.

OpenStudy (anonymous):

yea thanks! kudos !

OpenStudy (anonymous):

Yup np.

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