Yes . . im back with another question :((
http://prntscr.com/8gfbwi
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OpenStudy (anonymous):
Ok so look at the question. What are the odds someone will get a shot in every free throw?
OpenStudy (anonymous):
1 shot ? or would it have to add up to 5000?
OpenStudy (anonymous):
im guessin it going to be between A or B
OpenStudy (anonymous):
ok. Good its about one shot guessing. But realize that this will be simulated 5000 times.
This means \[5*5000=25000\]
That means there will be 25,000 shots total.
OpenStudy (anonymous):
So in about 419 of those simulations you will have a missed free throw ?
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OpenStudy (anonymous):
Wait.
OpenStudy (anonymous):
or ? .162*5000=810
OpenStudy (anonymous):
5000-810=4190
OpenStudy (anonymous):
Seeing this again. It would seem that it would probably be about 4190.
OpenStudy (anonymous):
correct it was thanks !
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OpenStudy (anonymous):
Wait which one?
OpenStudy (anonymous):
4190 was correct indeed !
OpenStudy (anonymous):
.162*5000=810
then 5000-810=4190
OpenStudy (anonymous):
ok. :P I was thinking something else when I first glanced at it so lel.
OpenStudy (anonymous):
yea thanks! kudos !
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