(1 point) The polynomial of degree 5, P(x) has leading coefficient 1, has roots of multiplicity 2 at x=2 and x=0, and a root of multiplicity 1 at x=−3
Find a possible formula for P(x). I understand what multiplicity is, my question would be is that it says BOTH x=2 and x=0 have a multiplicity of 2, that doesnt make any sense to me.

Question

(1 point) The polynomial of degree 5, P(x) has leading coefficient 1, has roots of multiplicity 2 at x=2 and x=0, and a root of multiplicity 1 at x=−3 
Find a possible formula for P(x). I understand what multiplicity is, my question would be is that it says BOTH x=2 and x=0 have a multiplicity of 2, that doesnt make any sense to me.

ganeshie8 · Answer

Hint :
If $x=a$ is a root with multiplicity of $k$, 
then $(x-a)^k$ is a factor

anonymous · Answer

I should have clarified. Im confused because it says x=2 and x=0 both have a multiplicity of 2, that doesn't make any sense to me.