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Assume that the playbook contains 9 pasing plays and 11 running plays. The coach randomly selects 8 plays from the playbook. What is the probability that the coach selects at least 2 passing plays and at least 3 running plays?
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total no .of plays=20
yes
now atleast 2 means 2 or more than 2
now out of 20 he selects 8
so now we can have the combinations
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2 passing,6 running 3 passing,5 running 4 passing,4 running 5 passing,3 running
so 9c2*11c6+9c3*11c5+9c4*11c4+9c5*11c3
now calculate and get the answer
@ pulsified did you understand?
@Pulsified333
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so is the answer 117810/125970
yeah
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