Question

how do i factor this?

Answer 1

\[2x^2 + 7x + 3\]

Answer 2

i might know... multiply 2 • 3 = 6
split some way, 6 • 1 ?

Answer 3

6 + 1 = 7 ?

Answer 4

\(\large\color{black}{ 2x^2+7x+3 }\)
\(\large\color{black}{ 2x^2+3x+x+3 }\)
\(\large\color{black}{ 2x(x+3)+1(x+3) }\)

Answer 5

and then the very last step.

Answer 6

why did you add x? into the equation? ( second line in first post )

Answer 7

@SolomonZelman I'm still confused...

Answer 8

someone?

Answer 9

starting from your post:
```
6 + 1 = 7
```
2x2+7x+3
becones
\(2x^2+6x ~~+x+3\)
which can be written as
\(2x(x+3) ~~+1(x+3)\)
So factor out the common factor (x+3) gives
\((x+3)(2x+1) \)

Answer 10

thank you

Answer 11

you're welcome! :)