Question

Help with exponents.

MEDAL!!

Question posted below ...

Answer 1

\[7v^3 \times 10u^3v^5 \times 8uv^3\]

Answer 2

@jdoe0001

Answer 3

don't you multiply
\(\bf{7*10*8}\)
and add the exponents?

Answer 4

Okay so if we do that then we will have
\[7 \times 10 \times 8 = 560\]

But how do i add the exponents?

Answer 5

\(v^3+v^5+v^3=3+5+3=11\\v^11\\u^3+u^1\\3+1=4\\u^4\)

Answer 6

\(v^3+v^5+v^3=v^{11}\)

Answer 7

add numbers
keep same variable

Answer 8

So would my answer be 560v^11v^4 ?

Answer 9

@Hero

Answer 10

You wrote two v's your u variable is missing.

Answer 11

Sorry i meant 560v^11u^4

Answer 12

Am I correct?

Answer 13

I really need help on this.

Answer 14

@zzr0ck3r

Answer 15

Correct, sorry.

Answer 16

Okay thank you. So I am going to do the next one:
\[\large 9xy^2 \times 9x^5y^2\]

Answer 17

\[\large 9x^1y^2 \times 9x^5y^2 = 81x^6y^4\]

Answer 18

@Hero

Answer 19

correct

Answer 20

Can i check more with you?

Answer 21

absolutely :)

Answer 22

\[6m^3n^3 \times 8m^2n^3 = 48m^5n^6\]

Answer 23

correct again :)

Answer 24

\[6x^2 \times 6x^3y^4 = 36x^5y^4\]

Answer 25

correct :)

Answer 26

\[7u^2v^5 \times 9uv^3 = 63u^3v^8\]

Answer 27

correct (:

Answer 28

\[uv \times 4uv^5 = 4u^2v^6\]

Answer 29

and correct once again c:

Answer 30

\[10xy^3 \times 8x^5y^3 = 80x^6y^6\]

Answer 31

correct

Answer 32

\[3u^4v^5 \times 7u^2v^3 = 21u^6v^8\]

Answer 33

correct :)

Answer 34

\[(2x^2)^2 = 2x^4\]

Answer 35

\[(p^4)^4 = p^16\]

Answer 36

\[(2x^2)^2 = 2x^4\]

Answer 37

uh-oh

Answer 38

just in case if you want to ask for (p^4)^4, my answer is p^16

Answer 39

Use the formula

\(\bf\Huge (ab)^m = a^mb^m\)

Answer 40

That one is correct

For that question, in latex you have to put p^{16}

Answer 41

\[p^{16}\]

Answer 42

But \(\bf\Large (2x^2)^2 \neq 2x^4\)

Answer 43

So use the formula I gave you :)

Answer 44

\[\large 2^2 \times (x^2)^2\]

Answer 45

\[4 \times x^4\]
?

Answer 46

correct :D

Answer 47

@AbdullahM I juts want to make sure a couple more if u have no problem :)

Answer 48

I would love to :)

Answer 49

thank you!

Answer 50

\[(k^3)^4\]

Answer 51

= \[k^12 \]

Answer 52

correct :)

Answer 53

sorry i forgot the latex

Answer 54

\[k^{12}\]

Answer 55

OH wait..

Answer 56

\[7^2 \times k^2 = 12 \times k^2\]

Answer 57

i meant 14

Answer 58

\[\large 14 \times k^2\]

Answer 59

So the question is \(\bf\Large 7^2 \times k^2 = 14 \times k^2\)

Answer 60

yes am i correct?

Answer 61

No...

\(\bf\Large 7^2 = 7\times 7\neq 2\times 7\)

Answer 62

oh my god.. silly mistake ! sorry i meant to say 49 x k^2

Answer 63

good :)

Answer 64

\[\large (2b^2)^4 = 2^4 \times (b^2)^4 = 16b^8 \]

Answer 65

sorry but can u just say correct or incorrect really quickly? i need to go.

Answer 66

correct

Answer 67

sorry, I was looking at another tab :p

Answer 68

thank you so much for ur help! i truly appreciate it :)

Answer 69

sorry one quick question

Answer 70

sure :D

Answer 71

\[2n^4 \times 5n^4 = 10n^8\]

Answer 72

and \[2n^4 \times 6n^4 = 12n^8 \]

Answer 73

those are basically the same

Answer 74

correct for both :D