Question

URGENT! HELP PLEASE, I'LL REWARD YOU
solve f(x) =x^2-4x+3
show work

Answer 1

@mathmate

Answer 2

@mathlover2014

Answer 3

Solve for x?

Answer 4

for f(-2)

Answer 5

@LifeIsADangerousGame

Answer 6

Oh, okay. So when it says solve for f(x) = x^2-4x+3 when f(-2) it means plug in -2 for x in the equation. So:
f(-2) = -2^2 - 4(-2) + 3 =

Answer 7

im so confused. i was taught to substitute f(x) with y

Answer 8

can you help me please and show the work? cause i know after that i have to switch out the variables

Answer 9

and i have to turn this in within the next 5 minutes

Answer 10

i will help too

Answer 11

thank you!

Answer 12

Okay:
f(x) = x^2-4x+3
f(-2) = (-2)^2-4(-2)+3
f(-2) = 4 + 8 + 3
f(-2) = 15

Answer 13

what does the sign right next to the x mean

Answer 14

Where at?

Answer 15

in the question it says x^

Answer 16

so what does this ^ mean?

Answer 17

f(x) IS y, but in this case you would not put -2 for y because this is not that type of problem.
^ means exponent. So x^2 is the same as \[x ^{2}\]

Answer 18

oh thank u

Answer 19

NP

Answer 20

Pro tip: Often times, when you plug in -2^2 or something similar into a calculator, the calculator will read it is -(2^2) and will give you the wrong answer. To prevent this, plug in (-2)^2, this forces the calculator to realize you are squaring a negative number.

Answer 21

here is the real answer:

Answer 22

ax^2+bx+c
x^2-4x+3
(x-3)(x-1)=0
x=3, x=1 when y=0
The graph of the parabola has a minimum because a is positive.
(3+1)/2=2 so y will be at a minimum when x=2
f(x)=y=2^2-(4*2)+3
=4-8+3

Answer 23

may i have my reward now?

Answer 24

after all i did answer ur question

Answer 25

@rosamartinez
"solve" and "evaluate/calculate" have different meanings in mathematics.

For your information, to "solve" means to find the unknown given and equation, for example,
solve 5x+3=18, then we "solve" by isolating x on the left, and find that x=3.
When we are given all information to calculate the value of a function, we say
"evaluate" f(-2), since x=-2, and the function is given/defined.
For the given case, we can "solve" f(x)=x^2-4x+3=0 (if =0 was given)
in which case f(x)=(x-3)(x-1)=0, or x=3 or x=1.

or
"evaluate" f(-3), then f(-3)=(-3)^2-4(-3)+3=9+12+3=24.