The number of ways in which four particular persons A,B,C,D
and six more persons can stand in a queue so that A always
stands before B, B before C, and C before D, is ?

Question

mathmath333 · Answer

$\large \color{black}{\begin{align}
& \normalsize \text{ The number of ways in which four particular persons A,B,C,D }\hspace{.33em}\~\
& \normalsize \text{ and six more persons can stand in a queue so that A always }\hspace{.33em}\~\
& \normalsize \text{ stands before B, B before C, and C before D, is ? }\hspace{.33em}\~\
\end{align}}$

dan815 · Answer

|dw:1442643874411:dw|