Question

http://prntscr.com/8icsqs

Answer 1

@hartnn

Answer 2

16 is the square of which number?

Answer 3

4

Answer 4

yeah

so we have
\(x^2-4^2 \)

use the formula
\(\Large a^2-b^2 = (a+b)(-b)\)

so \(x^2-4^2 = ...?\)

Answer 5

my answer would be c?

Answer 6

no

Answer 7

HINT: this is the exact same question as last time

Answer 8

its b

Answer 9

u can write that as \[x^2-4^2\] nd then use the identity\[a^2-b^2=(a+b)(a-b)\]

Answer 10

correct

Answer 11

Thanks!

Answer 12

\(x^2-16=0\implies x^2=16\implies x=\pm\sqrt{16}=\pm4\)

Answer 13

remember, that when you induce the square you get two answers.

Answer 14

what I mean by that is that when you have x^2=16 you get two answers, but if I ask you what sqrt(16) is, then it is 4

Answer 15

oh ok ty