Mathematics
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OpenStudy (sloppycanada):
Find f(g(x)) if f(x) = 2x + 1 and g(x) = x2 - 1.
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OpenStudy (jhannybean):
Wherever you see an x in your function for f(x) replace it with the function of g(x). \[f(g(x)) = 2(x^2-2)+1\]
OpenStudy (anonymous):
did u understood?
OpenStudy (sloppycanada):
\[2x^2-3\]
@Jhannybean
OpenStudy (sloppycanada):
but that's not one of my choices.
OpenStudy (jhannybean):
What are your answer choices?
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OpenStudy (anonymous):
ok \[f(g(x))= 2(x ^{2}-1)+1\]
OpenStudy (anonymous):
\[f(g(x))=2x ^{2}-2+1\]
OpenStudy (anonymous):
2(x^2-1)+1 = 2x^2 -2 + 1 = 2x^2 - 1
OpenStudy (jhannybean):
Oh, I made a typo there.
OpenStudy (jhannybean):
The \(x^2-2\) should have been \(x^2-1\)
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OpenStudy (anonymous):
\[f(g(x))= 2x ^{2}-1\]
OpenStudy (anonymous):
hope this helps :)
OpenStudy (jhannybean):
No harm in correcting me :)
OpenStudy (anonymous):
f(g(x)) = 2(g(x)) +1 = 2(x^2-1)+1
OpenStudy (sloppycanada):
So this one - Find g(f(x)) if f(x) = 2x - 3 and g(x) = x - 1.
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OpenStudy (sloppycanada):
Should be -
\[2x^2 + x -3\]
OpenStudy (anonymous):
g)x)-1 = (2x-3)-1 = 2x-4
OpenStudy (sloppycanada):
Find f(g(x)) if f(x) = 2x + 1 and g(x) = x2 - 1.
My answer options are -
2x -1
\[2x^2-1\]
\[2x^2 + 1\]
\[2x^3-1\]
OpenStudy (sloppycanada):
So if it's f(g(x)), shouldn't it be something along the lines of - (x^2 - 1)(2x+1)?
OpenStudy (jhannybean):
We've done this one.
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OpenStudy (jhannybean):
Just scroll up?
OpenStudy (sloppycanada):
It's just 2x -1 ?
OpenStudy (jhannybean):
You're not multiplying anything actually, you're just substituting the function of g(x).
OpenStudy (sloppycanada):
Wait what? I am very confused.
OpenStudy (jhannybean):
\[f(g(x))= f(x^2-1) = 2(x^2-1)+1 = 2x^2-2+1 =2x^2-1\]
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OpenStudy (jhannybean):
Do you see it now, @sloppycanada ?
OpenStudy (sloppycanada):
Kind of..
OpenStudy (jhannybean):
which part is confusing you?
OpenStudy (sloppycanada):
Where the "x" in 2x-1 went.
OpenStudy (jhannybean):
It was replaced by g(x)
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OpenStudy (sloppycanada):
Okay, so in this - Find g(f(x)) if f(x) = 2x - 3 and g(x) = x - 1.
It'd just be 1(2x -3) - 1?
OpenStudy (jhannybean):
Not quite, \[g(f(x)) = g(2x-3)= (2x-3)-1 = 2x-4\]
OpenStudy (sloppycanada):
Okay so again - Find (f – g)(x) if f(x) = 2x – 6 and g(x) = 3x + 8.
(2x -6) - (3x+ 8) = -x +2?
OpenStudy (jhannybean):
Somewhat, but a small math error. \[(f-g)(x) = f(x) - g(x) = (2x-6)-(3x+8) = -x-(8+6) = -x-14\]
OpenStudy (jhannybean):
You've got the idea though :D
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OpenStudy (sloppycanada):
Find (f + g)(x) if f(x) = 1/2x + 4 and g(x) = -x - 3.
(1/2x +4) + (-x-3) = -1/2 + 1
OpenStudy (sloppycanada):
-1/2x* +1?
OpenStudy (jhannybean):
Yep
OpenStudy (sloppycanada):
Find the zeros of -4x + 6