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OpenStudy (a1234):
Θ is an angle in quadrant 4 in which secΘ = 4. Use a trig identity to find the exact value of tanΘ. I used 1 + tan^2Θ = sec^2Θ. I got tan^2Θ = 15, but since tan is in quad 4, I think tanΘ = -sqrt15. Is this right?
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OpenStudy (a1234):
@jim_thompson5910
jimthompson5910 (jim_thompson5910):
\[\Large \tan(\theta) = -\sqrt{15}\] is correct
OpenStudy (triciaal):
|dw:1442806948688:dw|
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