MEDAL AND FAN PROMISED!!! PLZ HELP!!!
f(x) = 2(3)x, Section A is from x = 0 to x = 1 and Section B is from x = 2 to x = 3
can you help me find the rate of change @kiamousekia
\(\large\color{black}{f(x)=2(3)^x}\) Like this?
yes
\i need to find the rage of change
with that formula
@kiamousekia can u help me plz
How would you normally find the slope between the slope between points \(\large\color{black}{(a,b)}\) and \(\large\color{black}{(c,d)}\) ? \(\large\color{black}{m=\dfrac{b-d}{a-c}}\)
For section A, you need to find f(0) and f(1), and then the slope between (0,f(0)) and (1,f(1)).
well i need 2 Find the average rate of change of each section.
so ik that formula
but i need help doing it
ok, and tell me what is f(0)=? and f(1)=?
(0,1)?
\(\large\color{black}{f(x)=2(3)^x}\) \(\large\color{black}{f(0)=2(3)^0=?}\) \(\large\color{black}{f(1)=2(3)^1=?}\)
(anything raised to power 0, is 1)
so i need 2 answer that equasion
Idk sorry
yes, you need to answer my 2 last questions (those are your y-values of the 2 points, respectively) and then use the slope formula
f(x) = 2(3)x, Section A is from x = 0 to x = 1 and Section B is from x = 2 to x = 3 this is what im asking tho i need to find them sepretly
I know.
You have to know the y-coordinates of the 2 points to find the slope, don't you?
ok ok i got it now
What is the y-coordinate when x=0? What is the y-coordinate when x=1?
(recall that your function is \(\large\color{black}{f(x)=2(3)^x}\) )
plug in 0 for x, and then plug in 1 for x.
so its 6 and there are no soulutions 2 the first 1
\(\large\color{black}{f(x)=2(3)^x}\) \(\large\color{black}{f(0)=2(3)^0=2\cdot1=2}\) So the y-coordinate when x=0, is y=2
Can you find the y-value when x=1? (do it same way I have done it)
im so confused
and im so sorry
@Preetha @perl can you plz help
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