Question

Find the equation of the tangent plane to the sphere (x-1)^2 +(y+1)^2 + (z-2)^2 = 6 at the point (1,-2,0)

Answer 1

I'm just so confused about the geometry of it especially since (1,-2,0) is not on the sphere

Answer 2

Suppose f has a continuous partial derivatives. An equation of the tangent plane to the surface
\[z=f(x,y)\]
at the point
\[P(x_0,y_0,z_0)\]
is
\[z−z_0=fx(x_0,y_0)(x−x_0)+fy(x_0,y_0)(y−y_0)\]

Answer 3

Ohh, okay. Then I cant help you, sry.

Answer 4

No problem thanks for trying. Maybe someone else can