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Find the equation of the tangent plane to the sphere (x-1)^2 +(y+1)^2 + (z-2)^2 = 6 at the point (1,-2,0)
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I'm just so confused about the geometry of it especially since (1,-2,0) is not on the sphere
Suppose f has a continuous partial derivatives. An equation of the tangent plane to the surface \[z=f(x,y)\] at the point \[P(x_0,y_0,z_0)\] is \[z−z_0=fx(x_0,y_0)(x−x_0)+fy(x_0,y_0)(y−y_0)\]
Ohh, okay. Then I cant help you, sry.
No problem thanks for trying. Maybe someone else can
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