Question

I need help! Will medal and fan with testimonial!
No straight up answers please.

Answer 1

Here is link to problem I need help with http://i.imgur.com/fgRmRoV.png

Answer 2

pick two points on the line first
so we can use that

Answer 3

Okay what about 4,5 and 2,3

Answer 4

the line doesn't seem to touch those points though
goes close by, but doesn't seem those points are ON the line

Answer 5

OHH sorry

Answer 6

2,2 and 4,5?

Answer 7

same issue, those two points are not ON the line

Answer 8

Are you sure? I must be blind...

Answer 9

yes, I have the pictured zoomed in

Answer 10

5,6 -5,-6?

Answer 11

those will work
well, to get the slope is simple then
\(\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({\color{red}{ 5}}\quad ,&{\color{blue}{ 6}})\quad
% (c,d)
&({\color{red}{ -5}}\quad ,&{\color{blue}{ -6}})
\end{array}
\\\quad \\
% slope = m
slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies
\cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}}\)

Answer 12

okay give me a second and i will check answer with you

Answer 13

It's 0, 0?!?

Answer 14

well, 0,0 is ON the line, yes
is not the slope though

Answer 15

When I did the formula I got 0, 0. I'm sorry I am really horrible at math...

Answer 16

Can you show us how you got that?

Answer 17

0,0? the slope is a value alone, not an ordered pair though

Answer 18

-10, -12?

Answer 19

Oh wait I didn't read what you just put.

Answer 20

0.83 is the slope?

Answer 21

well
\(\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({\color{red}{ 5}}\quad ,&{\color{blue}{ 6}})\quad
% (c,d)
&({\color{red}{ -5}}\quad ,&{\color{blue}{ -6}})
\end{array}
\\\quad \\
% slope = m
slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies
\cfrac{{\color{blue}{ -6}}-{\color{blue}{ 6}}}{{\color{red}{ -5}}-{\color{red}{ 5}}}\implies \cfrac{\cancel{-12}}{\cancel{-10}}\implies \cfrac{6}{5}\)

Answer 22

6/5 is the answer?

Answer 23

yeap

Answer 24

:D thank you!