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How do extraneous solutions arise from radical equations?
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this is pretty simple, say for example the problem is 7l-2x+5l+3>5x-8
-2x+5>(5/7)x-(11/7) and -2x+5>-(5/7)x+(11/7) would be yours starting points for solving this
an extraneous solution can only occur when there is a variable on both sides of the inequality sign, so one of the answers you'll get from this might not be a real solution to the problem
(sry i forgot its 2x not -2x...)
so x>16/3 and x>5/3 (or something like that, for the second one) but since they both are greater than but its an and statement, the extraneous solution is x>5/3 since they both get to the right point, sry if that was complicated
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