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Physics 10 Online
OpenStudy (yumyum247):

LuLu!!! :D

OpenStudy (inkyvoyd):

what work (no pun intended) have you done so far?

OpenStudy (yumyum247):

the work of writing out the question....no pun intended!! :D

OpenStudy (inkyvoyd):

well go make some progress. at least draw a fbd

OpenStudy (yumyum247):

nnah i was joking.... i've done some of the questions but they are tooo long and difficult to type it here....

OpenStudy (yumyum247):

for the first question this is what i did...

OpenStudy (yumyum247):

first i figured out the normal force the earth was exerting the block of wood. Normal force = mass x gravity normal force = 0.72Kg X 9.80m/sec^2 Normal force = 7.05N This is my normal force.

OpenStudy (inkyvoyd):

looks good

OpenStudy (yumyum247):

from here i used te frictional formula to get my force of friction. Force of friction = μk x 7.05N Force of friction = 4.51N i got my friction.

OpenStudy (yumyum247):

Nor that i ad my frictinal force and normal force. i plugged them into te formula to get my net force Applied force - frictional force = m x change in velocity/time Applied force - 4.51N = 0.72Kg x 0.8m/sec^2 Applied force = 4.51N + 0.57N Applied force = 5.08N HEre is te answer to my first question....

OpenStudy (yumyum247):

now have absolutely no clue as to what do i need to do for te next question -_-

OpenStudy (inkyvoyd):

applied force is C.

OpenStudy (inkyvoyd):

you actually already finished the question lol

OpenStudy (yumyum247):

what chu mean o_o

OpenStudy (yumyum247):

can i use the force of friction for te second question???????????

OpenStudy (inkyvoyd):

applied force - frictional force = net force

OpenStudy (yumyum247):

i got that but help me here for a sec, can i use the frictional force tat i got for the second question

OpenStudy (inkyvoyd):

yes. that's why i said you did the problem already

OpenStudy (yumyum247):

aaitt....:D

OpenStudy (yumyum247):

now last thing...

OpenStudy (yumyum247):

how do i do the last question?!?!?!?!

OpenStudy (inkyvoyd):

silly. you started out by doing the last question.

OpenStudy (inkyvoyd):

applied force= actual force.

OpenStudy (yumyum247):

what chu mean?!?!?!?

OpenStudy (inkyvoyd):

Applied force - frictional force = m x change in velocity/time Applied force - 4.51N = 0.72Kg x 0.8m/sec^2 Applied force = 4.51N + 0.57N Applied force = 5.08N =>applied force is the actual force frictional force is the answer to part b m x change in velocity/time is net force

OpenStudy (yumyum247):

so my applied force is te actual force....O_O

OpenStudy (yumyum247):

LOL i didn't know i am so genius :D Thanks LOve

OpenStudy (inkyvoyd):

yeh.. net force is the sum of all forces.

OpenStudy (yumyum247):

aigt...i need to go to the washroom.............................:"D

OpenStudy (yumyum247):

@so before you go, the frictional force = 4.51N right? and the actual applied force = 5.08N The net force would be 5.08N - 4.51N = 0.57N right?!?!?!

OpenStudy (yumyum247):

@inkyvoyd please come back :(

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