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Mathematics 21 Online
OpenStudy (anonymous):

You reach into a bag of coins and withdraw two coins. What is the probability you withdrew a nickel and then a dime if the bag held five pennies, ten nickels and four dimes ?

OpenStudy (sleepyhead314):

mmm I'm not the best at probability, but I know that we should definitely first find out how many coins there are in total so 5 pennies + 10 nickles + 4 dimes = [how many coins?]

OpenStudy (anonymous):

19 coins

OpenStudy (sleepyhead314):

good :) then the chance of getting a nickel on the first try is [number of nickles] / [total number of coins] = ?

OpenStudy (anonymous):

Even though they separate the coins into categories, they are still in one group, so combine everything except the nickels and dimes.

OpenStudy (anonymous):

20 / 171

OpenStudy (sleepyhead314):

whoa there number of nickles = 10 total number of coins = 19 10 / 19 is the chance of pulling a nickel on the first try

OpenStudy (sleepyhead314):

then after we take the nickel out we are left with a total of \(18\) coins total right?

OpenStudy (anonymous):

yes

OpenStudy (sleepyhead314):

then the chance of pulling a dime next is [number of dimes] / [new total number of coins] = ?

OpenStudy (anonymous):

1.8

OpenStudy (sleepyhead314):

oh oh oh oh right I was taking one step at a time but the 20 / 171 answer you gave before is correct ^_^"

OpenStudy (anonymous):

okay thank you

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