How many solutions does the equation have? https://static.k12.com/bank_packages/files/media/mathml_d2827a10ceec63d33a2559e5da88e467718e4495_1.gif A. one solution B. infinite solutions C. no solution
Have you tried to solve it yet?
yes
Alright and can you show me the work?
no i did it in mah head sorry
i think its c
i just want to know if its correct
Thats not correct
ok
3(4x−3)−7x=5x−9 (3)(4x)+(3)(−3)+−7x=5x+−9(Distribute) 12x+−9+−7x=5x+−9 (12x+−7x)+(−9)=5x−9(Combine Like Terms) 5x+−9=5x−9 5x−9=5x−9 Subtract 5x from both sides. 5x−9−5x=5x−9−5x −9=−9 Add 9 to both sides. −9+9=−9+9 0=0 <----when the same number equals each other it means that there are infinite solutions.
ohhhhhhhhhhhhh ok
:)
can you elp with a couple others
Well i'm in school so ill help u with what i can until my free period is over :)
ok
Which expressions would complete this equation so that it has one solution? 4(2x – 3) – 4x = Choose exactly two answers that are correct. A. 4x – 12 B. 3x – 4 C. 3(2x – 6) D. 4(x – 5)
I recommend trying each options out
4(2x−3)−4x=4x−12 (4)(2x)+(4)(−3)+−4x=4x+−12(Distribute) 8x+−12+−4x=4x+−12 (8x+−4x)+(−12)=4x−12(Combine Like Terms) 4x+−12=4x−12 4x−12=4x−12 Step 2: Subtract 4x from both sides. 4x−12−4x=4x−12−4x −12=−12 Step 3: Add 12 to both sides. −12+12=−12+12 0=0 <----is this one solution?
no
or idk
4(2x−3)−4x=3x−4 (4)(2x)+(4)(−3)+−4x=3x+−4(Distribute) 8x+−12+−4x=3x+−4 (8x+−4x)+(−12)=3x−4(Combine Like Terms) 4x+−12=3x−4 4x−12=3x−4 Step 2: Subtract 3x from both sides. 4x−12−3x=3x−4−3x x−12=−4 Step 3: Add 12 to both sides. x−12+12=−4+12 x=8 Answer: x=8 <----is that one solution?
oh no its infinite
thst is one the other is infinite
Yes what about the 2nd one?
its one answer right?
Yep
sooo imma say its b and c am i correct
ok
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