Question

Did I get this right?

Factor: a^3y+1

I got
(a^y+1)(a^y-1)

Answer 1

(a^y+1)(a^y-1)

multiply them and see if you get back the original expression

Answer 2

Give me one second. :-)

Answer 3

I got a^y2-1a^y-1

Answer 4

I think you will get : [a(^y)^2 - 1^2] after multiplying (a^y+1)(a^y-1)

Answer 5

Well, it appears that I don't know how to do it. Can someone perhaps explain. @ganeshie8

Answer 6

@doddle

Answer 7

Hmm it is really simple just remember this equation:

a^3y+1 is a sum of cubes. a^3+b^3= (a+b) (a^2-ab+b^2)

So, a^3y+1= (a^y+1)(a^2y-a+1)