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Use substitution to solve the system. 2x+3y=10 y=3x+7
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@Nnesha @phi
@zepdrix
the second equation tells you that y EQUALS 3x+7 SO Go to the first equation - and wherever there is a y you can write 3x+7 when you do that you can see that there is only x in the new equation - so you can work out x Do that first...
2x+3(3x+7)= 10?
yes- good now distribute the 3 into th ebracket - and collect 'like terms' together
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