Please help? A gambler has developed a weighted six-sided die with sides marked 1, 2, 3, 4, 5, 6. The probability of rolling a 6 is 0.4 and all other sides are equally likely. (X is a random variable). What is the probability that an even number is rolled?
hello
do you need help
Yes, please
I do not understand how to find this probability
well do you know probabilities
Yes I do, but what I am confused about is that he gave us an assigned probability. Usually the probability for rolling a dice is 1/6, but he made it .4 and that confuses me.
ok so you know that the probablilty of rolling two is 1/6 right
or am i wrong
Yes, that is correct
well it is confusing but what is your best guess
we know all of them have a probibility of 1/6 so what u do with the 0.4 is divide or multiply
Multiply?
yes correct
and the equation is
0.4 *6 correct
I thought you said multiply. So wouldn't it be 0.4 x 1/6?
the * is the multivly sign
and the / is division
so after you multiply
u get ??
2.4?
correct
and thats your answer 2.4 you get it
Where did the 6 come from though? I thought we were using 1/6. So wouldn't 0.4 x (1/6)= .0667?
ik
but we have to multiply th ewhole number and then
I thought probability was supposed to be between 0 and 1
@Rushwr
no its one through 6
so if yyou peice it all together 0.4x6=2.4 And that peices it all together
u get it
maybe you can help him understand rushwer
Soo basically what u have to know is when u add all the probabilities they should be equal to 1
yes they do 1/6+1/6 ect.
and youll get 1 once you add them all and thank you so much rushwer for your help
i really appreciate it
P1 = probability of rolling 1 P2 = probability of rolling 2 P3 = probability of rolling 3 P4= probability of rolling 4 P5= probability of rolling 5 P6 = Probability of rolling 6 P1+P2+P3+P4+P5+P6 = 1
yea thats what i meant too thats what i was trying to help him get in my equation
Except for P6 others are same right? so we can say P1=P2=P3=P4=P5 so instead of P1+P2+P3+P4+P5 we can right 5P1 right?
yea
So do you get it now
@tennis96
so 5P1 + P6 = 1 We know P6 = 0.4 So 5P1 = 1-0.4 = 0.6 So P1 = 0.6/5 = 0.12 Except for the probability of rolling 6 other probabilities are 0.12
yea correct
But it says all other sides are equally likely. So that means the probability of rolling a 6 is 0.4. And the probability or rolling either a 1,2,3,4, or 5 is 0.4 as well?
That is ; P1= 0.12 P2 = 0.12 P3 =0.12 P4 = 0.12 P5 = 0.12 P6 = 0.4 Now add up the probabilities of the even numbers ! That is P2+P4+P6 Then u get the probability of rolling an even number
yea do you get it now tennis
OHH it just clicked
So all the other trials would have to be equal to 0.6 right? so 0.6/ 5= .12
yes thank you so much for letting us help you
i have a great time personaly helping students find there way
Thank you!
your wekcome thank you or letting us help you
"The probability of rolling a 6 is 0.4 and all other sides are equally likely" this what the question said. I think u took it wrong !!! This means probability of rolling 6 is 0.4 and all the others equal. But this doesn't mean all the other sides are equal to 0.4 . Simply it says the probability of rolling 6 is different than the others
Yeah I did haha! thanks for pointing this out to me Rusher!
Rushwr* lol no problem !!!!
can i have a medal plzz
i helped too lol
im just kidding i dont care about medals i just care about helping other students
okai Done ! I gave u a medal !!!!!
thnx
I hope u got the answer right 11 @tennis96 Can I know ur answer before I leave this ?
No problem :)
yea thats what i asked too
I'm guessing I add all the probabilities together. P(2)= .12 P(4)=.12 P(6)= .4. Added together is this ..
.64?
Correct !!!!
Okay perfect thank you :)
yes you are correct
Anytym :)
thank you for everything
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