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Mathematics 13 Online
OpenStudy (annie96):

What is the domain of k(x)=sqrt(x+4? A. all real numbers greater than or equal to 4. B. all real numbers greater than 0. C. all real numbers. D. all real numbers greater than or equal to 0.

hartnn (hartnn):

The quantity inside square root must be non-negative to get a real domain

hartnn (hartnn):

so solve for x in \(\Large x+4 \ge 0\)

OpenStudy (danjs):

The domain are the possible values you can pick for X and get a Y value that makes sense

OpenStudy (danjs):

real

OpenStudy (annie96):

Domain: [−4,∞),{x|x≥−4} Range: [0,∞),{y|y≥0}

hartnn (hartnn):

yup thats correct

OpenStudy (annie96):

so its a

OpenStudy (danjs):

fancy, set , notation

hartnn (hartnn):

your option A should have a -4 instead of 4 there.

OpenStudy (danjs):

yes the domain includes all the values possible for X that map to a value for Y

OpenStudy (annie96):

Thanks you guys.

OpenStudy (danjs):

y = root(x)|dw:1443162234484:dw|

OpenStudy (danjs):

no values are to left of y=0, welcome

OpenStudy (danjs):

x=0, sorry

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