Question

Select the equation in which the graph of the line has a negative slope, and the y-intercept equals -5.



10x + 5y = –25


5x – 10y = –12


20x + 5y = 50


2x + 6y = 10
Select the equation that contains the point (3, -9), and in which the graph of the line has a positive slope.



y – 9 = –4(x + 3)


y + 9 = 4(x – 3)


y – 9 = 4(x + 3)


y + 9 = –4(x - 3)

http://prntscr.com/8k86m8

Answer 1

@DanJS

Answer 2

you can put each answer into the y = m*x + b form and check

Answer 3

for the 1st one is it the 1st answer ? @DanJS

Answer 4

or graph by plotting the x and y intercepts and check which has a negative slope, and y=-5 when x=0

Answer 5

solve it for y

10x + 5y = -25

5y = -10x -25

y = -2x - 5

Answer 6

y=mx+b form, m is the slope and b is the y intercept value

Answer 7

so the first answrr would be B?

Answer 8

my mistake A?

Answer 9

yes

Answer 10

cool

Answer 11

the second recall thee slope - point form , you can read a point on the line directly from the equation...

Answer 12

y - y1 = m*(x - x1)

the point (x1, y1) is on the line, and the slope is m

Answer 13

they want positive m value, so +4 ,
and (x1 , y1) = (3, -9)

Answer 14

so would the answer be C?

Answer 15

y - (-9) = m*(x - 3)

Answer 16

watch the signs

Answer 17

True, so it would be B

Answer 18

yeah noh !!!!

Answer 19

what do u think about the last question ?

Answer 20

i was thinking A

Answer 21

yeah that's correct

Answer 22

k thanks

Answer 23

no problem :)

Answer 24

same as the first question, inspect after solving for y=mx+b form