Question

(will give medal) factor by grouping
uy + 3u - 2y - 6

Answer 1

(u-2)(y+3)

Answer 2

can you explain how you did it?
(i'm having a major brain fart rn)

Answer 3

HI!!

Answer 4

it says "factor by grouping" right?

Answer 5

yes

Answer 6

\[\color{red}{uy + 3u} -\color{blue}{ 2y - 6}
\]

Answer 7

common factor of \(u\) in the red part, and \(2\) in the blue part

Answer 8

\[\color{red}{u(y+3)}+\color{blue}{-2(y+3)}\]

Answer 9

now each term has a common factor of \(y+3\) giving you
\[(u-2)(y+3)\]

Answer 10

oh okay thank you that makes a lot more sense @misty1212