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OpenStudy (anonymous):
@Nnesha can you please help me
Nnesha (nnesha):
we need to use formula f(x+h)-f(x) over h right ?
OpenStudy (anonymous):
instead of x im using a but yes
OpenStudy (anonymous):
f(a)= (2a)/(a-1)
Nnesha (nnesha):
ohh okay so first we have to find f(a+h)
substitute a for a+h
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OpenStudy (anonymous):
and f(a+h)= (2a+2h)/(-a-h)
OpenStudy (anonymous):
am i correct
Nnesha (nnesha):
the denominator would be a-1 = (a+h)-1
so it would be a+h-1 it's not a multiplication
OpenStudy (anonymous):
oh alright
Nnesha (nnesha):
alright so now we can substitute f(a+h) for that into the formula \[\huge
\rm \frac{ \frac{ 2a+2h }{ a+h-1 } +\frac{ 2a }{ a-1 } }{ h }\]
now find the common denominator
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OpenStudy (anonymous):
so you multiply it by h?
Nnesha (nnesha):
first deal with the numerator
2a+2h/a+h-1 + 2a/a-1
OpenStudy (anonymous):
what about it
Nnesha (nnesha):
what would be the common denominator ?
Nnesha (nnesha):
brb i'll login to other laptop
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OpenStudy (anonymous):
shouldnt it be a+h-1?
Nnesha (nnesha):
both denominator are not the same so we should multiply both denominator \[\huge\rm \frac{ (\color{Red}{a-1})(2a+2h) + 2a(\color{blue}{a+h-1}) }{ (a+h-1)(a-1)}\]
and when we find common denominator
we should multiply numerator of first fraction by the denominator of 2nd fraction
Nnesha (nnesha):
and multiply the numerator of 2nd fraction with the denominator of first
OpenStudy (anonymous):
so what did get
Nnesha (nnesha):
|dw:1443222925608:dw|
kinda like cross multiplication