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how do i find the seconds it'll take If an object is projected upward from ground level with an initial velocity of 96ft/sec, its height h in feet after t seconds is given by the equation h=-16t^2+96t
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@Sooch ???
@Agl202 That's the whole problem on my worksheet and it then asks "After how many seconds does the object hit the ground?"
When it hits the ground, the height is \(\color{olive}{0}\). \( \color{blue}{h}=-16t^2+96t \) \( \color{blue}{0}=-16t^2+96t \) \(\tt{solve}~{for}~{\color{red}{ t.}}\)
so i factor out -16t+96?
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Exactly!
Yes. (Sooch I also typed a reply on your other question. )
okay thank you @mathway
\(\huge -16(t-6)=0\)
No problem!
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