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Mathematics 17 Online
OpenStudy (anonymous):

how do i find the seconds it'll take If an object is projected upward from ground level with an initial velocity of 96ft/sec, its height h in feet after t seconds is given by the equation h=-16t^2+96t

OpenStudy (agl202):

Question not finished...

OpenStudy (agl202):

@Sooch ???

OpenStudy (anonymous):

@Agl202 That's the whole problem on my worksheet and it then asks "After how many seconds does the object hit the ground?"

OpenStudy (anonymous):

When it hits the ground, the height is \(\color{olive}{0}\). \( \color{blue}{h}=-16t^2+96t \) \( \color{blue}{0}=-16t^2+96t \) \(\tt{solve}~{for}~{\color{red}{ t.}}\)

OpenStudy (anonymous):

so i factor out -16t+96?

OpenStudy (anonymous):

Exactly!

OpenStudy (defiance):

Yes. (Sooch I also typed a reply on your other question. )

OpenStudy (anonymous):

okay thank you @mathway

OpenStudy (anonymous):

\(\huge -16(t-6)=0\)

OpenStudy (anonymous):

No problem!

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