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What is the formula for factoring a^2+b^2?
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Specifically, my question is 8r^6+27s^12.
It concerns factoring.
\[a^2+b^2=a^2-(-b^2)=\left( a^2-\iota^2b^2 \right)=\left( a+\iota b \right)\left( a-\iota b \right)\]
Is there a more simple version of this formula @surjithayer ?
\[8r^6+27s^{12}=\left( 2r^2 \right)^3+\left( 3s^4 \right)^3=?\]
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Is that really the formula I need to use to solve the problem @surjithayer ?
yes \[a^3+b^3=\left( a+b \right)\left( a^2-ab+b^2 \right)\]
Ah, okay. Thank you. I am now going to work on it. :-)
That was a hard question. (2r^2+3s^4)(4r^4-6r^4s^6+9s^3)
yw
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R u asking what that is and its A²+b ²=c² and its called the pythagorean theorem
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