Did I do this right?
Rewrite f(x)=-3(x+2)^2+4 in standard form.
f(x)=-3(x+2)(x+2)+4
f(x)=-3(x^2+2x+2x+4)+4
f(x)=-3(x^2+4x+4)+4
f(x)=(3x^2-12x+-12)+4
f(x)=-3^2-12x+-12+4
f(x)=-3x^2+12x-8

Answer is f(x)=-3^2+12x-8

did I do this right or can you tell me where i went wrong?

Question

Did I do this right?
Rewrite f(x)=-3(x+2)^2+4 in standard form.
f(x)=-3(x+2)(x+2)+4
f(x)=-3(x^2+2x+2x+4)+4
f(x)=-3(x^2+4x+4)+4
f(x)=(3x^2-12x+-12)+4
f(x)=-3^2-12x+-12+4
f(x)=-3x^2+12x-8

Answer is f(x)=-3^2+12x-8

did I do this right or can you tell me where i went wrong?

nnesha · Answer

check 4th and last line 
there are sign mistakes

anonymous · Answer

but the end answer is right except for the sign errors? @Nnesha

nnesha · Answer

no the answer isn't correct  
sign $\huge\rm \color{red}{erro.Orr}$

nnesha · Answer

|dw:1443295691039:dw|

nnesha · Answer

-3 times x^2 = ?

anonymous · Answer

I redid my work and got $$f(x)=-3x^2-12x-16$$

nnesha · Answer

looks good

nnesha · Answer

oh hwait no

nnesha · Answer

how did you get -16? 
like i said before there are just sign mistakes

anonymous · Answer

at the end i had -12+4 ?

nnesha · Answer

yes right so -12+4 = ?

anonymous · Answer

so $$f(x)=-3x^2-12x-8$$ is right?

nnesha · Answer

|dw:1443299023462:dw|
yes right you forgot the negative at the end 
so it's -12