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how do i factor (p-q)(p+q)+(p-q) into (p−q)(p+q+1)?
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treat \((p-q) =a\) and \((p+q)=b\), it's easier to look at these if they're letters instead of big, scary terms
\[(p-q)(p+q)+(p-q) \implies ab+a\] That means if we factor out the common term \(a\) we would have \[=a(b+1)\]
Do you understand, @one2345 ?
yes
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thank you!
Np
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