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Chemistry 10 Online
OpenStudy (anonymous):

How to draw all the stereoisomers possible for the following molecules

OpenStudy (anonymous):

these I mean

OpenStudy (anonymous):

ok thank you

OpenStudy (photon336):

@C17H19NO3

OpenStudy (photon336):

Step #1 Identify chiral carbons. A chiral carbon is a carbon that has four different groups attached to it

OpenStudy (photon336):

|dw:1443409031254:dw|

OpenStudy (photon336):

|dw:1443409143801:dw| In our figure, you can clearly see that OH group a wedge means that the group is coming outwards, AT you, while a dashed line means the group is away not facing at you. On this carbon you can clearly see that this carbon is chiral with the OH group right? it has a CH3 group, an OH group, and a C carbon double bond. now what do we do now? for each stereo center there are two possible configurations, R and S. to assign these we must look at the atoms individually, and rank them according to their atomic weight, from a priority from 1-4. we must make sure that the group numbered 4 usually but not always is H is in the back. usually you just count the atoms, and then flip. so the heaviest elements get the highest priority 1. Oxygen bonded to the carbon is the highest so that gets labeled as 1. now we move over and see the other groups . the hydrogen bonded to the chiral carbon we label that 4. now we have two other groups a methyl group and a carbon attached to a double bond. for this we must look for the first point of difference. the first point of difference here is the double bond: notice a double bond means two carbon carbon bonds. so we have a for the CH3 1 carbon 3 hydrogens while for the double bond there are two carbons two hydrogens. the double bond gets designation 2 while the methyl group gets 3. @aaronq i could use your expertise to possibly identify any errors. |dw:1443409584603:dw|

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